A fair die was thrown three times and the outcome was repeatedly six. If the die is thrown again what is the probabilityof getting six?

Correct option is A

Given:

• A fair die was thrown three times, and each time the result was 6.
• It is now thrown again.
• We are asked: What is the probability of getting a 6 on this new throw?

Formula Used:

$$\text{Probability} = \frac{\text{Total number of favourable outcomes}}{\text{Total number of outcomes}}$$

Solution:

Sample space of throwing a die is {1, 2, 3, 4, 5, 6}

∴ The probability of getting a 6 is 1/6.

The given die was thrown three times and the outcome was repeatedly six.

If thrown again, then it is a new event, independent of the previous one.

∴ the probability remains the same.

Required probability is 1/6.