Two batteries having non-zero emf E₁ and E₂ have internal resistances r₁ and r₂ respectively. They are connected in parallel. Given E₂ > E₁. How about the equivalent emf E of the combination?

Correct option is C

Correct answer is C
Explanation:
The equivalent emf (E) for the parallel combination is calculated using:
E = (E1/r1 + E2/r2) / (1/r1 + 1/r2)
Since E2 < E1, and the weights depend on the inverse of r1 and r2, the following conditions hold:
E < E1
E > E2