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    An electric refrigerator rated 400 W operates 8 hours/day. What is the cost of the energy to operate it for 30 days at ₹3.00 per kW h?
    Question

    An electric refrigerator rated 400 W operates 8 hours/day. What is the cost of the energy to operate it for 30 days at ₹3.00 per kW h?

    A.

    ₹400

    B.

    ₹36

    C.

    ₹288

    D.

    ₹9.6

    Correct option is C

    Correct Answer: (C) ₹288

    Explanation:

    The cost of electricity is calculated using the formula:

    Energy Consumed=Power×TimeEnergy Consumed=Power×TimeTotalCost=EnergyConsumed×CostperunitTotal Cost=Energy Consumed×Cost per unitPower×Time\text{Energy Consumed} = \text{Power} \times \text{Time}Total Cost=Energy Consumed×Cost per unit\text{Total Cost} = \text{Energy Consumed} \times \text{Cost per unit}Power×TimeEnergy Consumed=Power×TimeTotalCost=EnergyConsumed×CostperunitTotal Cost=Energy Consumed×Cost per unit

    Step 1: Calculate daily energy consumption

    • Power rating of the refrigerator = 400 W = 0.4 kW
    • Time of operation per day = 8 hours

    Energy per day=0.4×8=3.2kWhEnergy per day=0.4×8=3.2 kWh=0.4×8=3.2 kWh\text{Energy per day} = 0.4 \times 8 = 3.2 \text{ kWh}=0.4×8=3.2kWhEnergy per day=0.4×8=3.2 kWh

    Step 2: Calculate total energy for 30 days

    Total Energy=3.2×30=96kWhTotal Energy=3.2×30=96 kWh96 kWh\text{Total Energy} = 3.2 \times 30 = 96 \text{ kWh}96kWhTotal Energy=3.2×30=96 kWh

    Step 3: Calculate total cost

    • Given cost per kWh = ₹3.00

    Total Cost=96×3=₹288Total Cost=96×3=₹288₹288\text{Total Cost} = 96 \times 3 = ₹288₹288Total Cost=96×3=₹288

    Key Points:

    • 1 kWh = 1 unit of electricity.
    • The power rating (W) should be converted into kW (divide by 1000) before calculations.
    • The cost calculation is based on multiplying total energy (in kWh) by the cost per unit.

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