Two identical bulbs are connected in parallel toe a battery of 4V. If the current is 0.2A, the power dissipated by the battery is :

Correct option is B

The correct answer is (b) 0.8 W.

The power dissipated by the battery can be calculated using the formula:

                                  $$P = V \times I$$​​

Where:

• V = 4V (Voltage of the battery)
• I = 0.2A (Total current supplied by the battery)

Substituting the values:

                           P=   $$4V \times 0.2A$$​= 0.8W

0.8 W) is correct, is the total power dissipated by the battery.

Information Booster:

Concepts Related to Power Dissipation in Electrical Circuits:

1. Power Dissipation Formulae:
• P = V × I (Basic formula using voltage and current)
• P = I² × R (Using resistance and current)
• P = $$\frac{V^2}{R}$$​(Using voltage and resistance)
2. Parallel Circuit Characteristics:
• Voltage (V) remains the same across all components.
• Total current (I) is the sum of currents through each branch.
3. Application in Electrical Devices:
• The total power supplied by a battery is distributed among the components connected to it.
• If bulbs are identical, power is equally divided.