Given:
Three times the first of three consecutive odd integers is 3 more than two times the third.
Solution:
Let the three consecutive odd integers be x, x+2, and x+4.
3x = 2(x+4) + 3
3x = 2x + 8 + 3
3x - 2x = 11
x = 11
So, the third integer is x + 4 = 11 + 4 = 15.
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