The product of two consecutive positive natural numbers is 812. The greater of the two numbers is:
Given:
Two consecutive natural numbers: n and n+1
Their product is 812
Find the greater number
Solution:
From the condition;
n(n+1) = 812
n^2 + n - 812 = 0
n^2 +29n - 28n - 812 = 0
n(n + 29) - 28(n + 29) = 0
(n - 28)(n + 29) = 0
n = 28 as numbers are natural
Thus Greatest number is n + 1 = 28 + 1 = 29
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