Given:
Ratio of ages = 4 : 7 : 9
Eight years ago, total age = 56
Solution:
Total age eight years ago:
(4x - 8) + (7x - 8) + (9x - 8) = 56
4x + 7x + 9x - 24 = 56
20x - 24 = 56
20x = 56 + 24
20x = 80
x = 80 / 20
x = 4
Ages of them -
The eldest is 36 years old now.
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Six times the present age of P exceeds the present age of Q by 46 years. After 10 years, six times Q’s age will be 18 years less than five times P’s age at that time. What is the present age of Q (in years)?
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If 2 times Mary's present age is 27 years more than 5 times Dia's present age, and 7 times Dia's present age is 9 years less than Mary's present age, then what is the difference (in years) between the ages of Mary and Dia?
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