Correct option is B
Given:
Let the present ages of P and Q be P and Q years respectively.
Six times the present age of P exceeds the present age of Q by 46 years:
6P - Q = 46
After 10 years, six times Q’s age will be 18 years less than five times P’s age at that time:
6(Q+10) = 5(P+10) - 18
Find the present age of Q.
Solution:
From equation (2):
6Q + 60 = 5P + 50 - 18
6Q + 60 = 5P + 32
5P - 6Q = 28.........(Equation A)
From equation (1):
6P - Q = 46 .............(Equation B)
Multiply Equation B by 6:
36P - 6Q = 276
Subtract Equation A from this:
(36P - 6Q) - (5P - 6Q) = 276 - 28
31P = 248
P = 8
Substitute P = 8 in Equation (1):
6(8) - Q = 46
48 - Q = 46
Q = 2
Present age of Q = 2 years
Alternate Solution:
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