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    The sum of the present ages of a father and his son is 75 years. Fifteen years ago, father's age was eight times the age of the son. After 7 years, so
    Question

    The sum of the present ages of a father and his son is 75 years. Fifteen years ago, father's age was eight times the age of the son. After 7 years, son's age will be

    A.

    29 years

    B.

    20 years

    C.

    23 years

    D.

    27 years

    Correct option is D

    Given:
    Sum of present ages: F + S = 75
    15 years ago: F - 15 = 8(S - 15)
    Formula Used:
    Linear equations in two variables.
    Solution:
    Let present age of Father be F and Son be S.
    From the first given condition: F = 75 - S.
    Substitute F into the second condition:
    75 - S - 15 = 8(S - 15)
    60 - S = 8S - 120
    60 + 120 = 8S + S
    180 = 9S
    S = 20
    The present age of the son is 20 years.
    The age of the son after 7 years will be = 20 + 7 = 27 years.
    Final Answer
    So the correct answer is (d)

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