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The sum of the present ages of a father and his son is 75 years. Fifteen years ago, father's age was eight times the age of the son. After 7 years, so
Question

The sum of the present ages of a father and his son is 75 years. Fifteen years ago, father's age was eight times the age of the son. After 7 years, son's age will be

A.

29 years

B.

20 years

C.

23 years

D.

27 years

Correct option is D

Given:
Sum of present ages: F + S = 75
15 years ago: F - 15 = 8(S - 15)
Formula Used:
Linear equations in two variables.
Solution:
Let present age of Father be F and Son be S.
From the first given condition: F = 75 - S.
Substitute F into the second condition:
75 - S - 15 = 8(S - 15)
60 - S = 8S - 120
60 + 120 = 8S + S
180 = 9S
S = 20
The present age of the son is 20 years.
The age of the son after 7 years will be = 20 + 7 = 27 years.
Final Answer
So the correct answer is (d)

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