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    The sum of the ages of a father and his son is 50 years. Five years ago, the father's age was 4 times his son's age. Find their present ages.
    Question

    The sum of the ages of a father and his son is 50 years. Five years ago, the father's age was 4 times his son's age. Find their present ages.

    A.

    Father : 35 years, Son : 15 years

    B.

    Father : 37 years, Son : 13 years

    C.

    Father : 40 years, Son : 10 years

    D.

    Father : 38 years, Son : 12 years

    Correct option is B

    Given:
    Present age sum: Father + Son = 50 years
    5 years ago: Father's age = 4 × Son's age
    Formula Used:
    Linear simultaneous equations.
    Solution:
    Let the present age of the father be F and the son be S.
    F + S = 50 => F = 50 - S
    Five years ago, their ages were F - 5 and S - 5 respectively.
    F - 5 = 4(S - 5)
    Substitute the value of F from the first equation into the second.
    (50 - S) - 5 = 4S - 20
    45 - S = 4S - 20
    45 + 20 = 4S + S
    65 = 5S
    S = 13
    Substitute S back into the first equation to find F.
    F = 50 - 13 = 37
    The present age of the father is 37 years and the son is 13 years.
    Final Answer
    So the correct answer is (b)

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