​Three numbers are in ratio 11 : 16 : 23. If their sum is 150, find the greatest number.

Correct option is D

Given:

Three numbers are in the ratio 11:16:23.

Sum of the three numbers = 150

Formula Used:

If numbers are in the ratio a:b:c, then the numbers can be represented as ax, bx, and cx, where x is a common factor.

Solution:

Let the three numbers be 11x, 16x, and 23x.

According to the given information:

11x + 16x + 23x = 150

50x = 150

x = 3

Greatest number = 23x = 23 $$\times$$​ 3 = 69

Therefore, the greatest number is 69.

Option (d) is right.