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    If  xy=43\frac{x}{y} = \frac{4}{3}yx​=34​​ then x−yx+y=\frac{x-y}{x+y} =x+yx−y​=​​
    Question

    If  xy=43\frac{x}{y} = \frac{4}{3}​ then xyx+y=\frac{x-y}{x+y} =​​

    A.

    4/3

    B.

    3/7

    C.

    7/1

    D.

    1/7

    Correct option is D

    Given
    xy=43\frac{x}{y} = \frac{4}{3}​​

    Solution
    Let x = 4k and y = 3k.

    We need to find the value of xyx+y \frac{x - y}{x + y}​​
    Substitute the values of x and y into the expression:
    =4k3k4k+3k =k7k =17= \frac{4k - 3k}{4k + 3k} \\ \ \\= \frac{k}{7k} \\ \ \\= \frac{1}{7}​​

    So the correct answer is (d)

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