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If  xy=43\frac{x}{y} = \frac{4}{3}yx​=34​​ then x−yx+y=\frac{x-y}{x+y} =x+yx−y​=​​
Question

If  xy=43\frac{x}{y} = \frac{4}{3}​ then xyx+y=\frac{x-y}{x+y} =​​

A.

4/3

B.

3/7

C.

7/1

D.

1/7

Correct option is D

Given
xy=43\frac{x}{y} = \frac{4}{3}​​

Solution
Let x = 4k and y = 3k.

We need to find the value of xyx+y \frac{x - y}{x + y}​​
Substitute the values of x and y into the expression:
=4k3k4k+3k =k7k =17= \frac{4k - 3k}{4k + 3k} \\ \ \\= \frac{k}{7k} \\ \ \\= \frac{1}{7}​​

So the correct answer is (d)

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