Correct option is B
Concept:
A single die has 6 faces, each face has an equal probability of appearing on a throw, making it 1/6.
Solution:
When three dice are thrown, the total number of outcomes is the total outcomes for each die multiplied together.
That is, 6 outcomes for the first die,
6 for the second, and
6 for the third,
giving a total of
63 = 216 possible outcomes.
The event of all three dice reading the same (for instance, all being 1s, 2s, etc.) has 6 possible outcomes:
(1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), and (6, 6, 6).
Therefore, the probability of all three dice reading the same is the number of successful outcomes divided by the total number of outcomes,
in this case,
=6/216
= 1/36.
