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    There are two numbers with the difference of 14 between them and the difference of their squares is 56. What are those numbers?
    Question

    There are two numbers with the difference of 14 between them and the difference of their squares is 56. What are those numbers?

    A.

    9, -5

    B.

    2, 16

    C.

    3, 17

    D.

    23, -9

    Correct option is A

    Given:

    Difference between two numbers = 14
    Difference of their squares = 56

    Formula Used:

    a2b2=(ab)(a+b)a^2 - b^2 = (a - b)(a + b)​​

    Solution:
    a2b2=56a^2 - b^2 = 56​​

    (a - b)(a + b) = 56

    14(a + b) = 56

    a + b = 5614=4\frac{56}{14} = 4

    a - b = 14

    a + b = 4

    Add equations:

    2a = 18

    a = 9

    b = a - 14 = 9 - 14 = -5

    The two numbers are 9 and -5.

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