There are two numbers with the difference of 14 between them and the difference of their squares is 56. What are those numbers?

Correct option is A

Given:

Difference between two numbers = 14
Difference of their squares = 56

Formula Used:

​$$a^2 - b^2 = (a - b)(a + b)$$​​

Solution:
​$$a^2 - b^2 = 56$$​​

(a - b)(a + b) = 56

14(a + b) = 56

a + b = $$\frac{56}{14} = 4$$​

a - b = 14

a + b = 4

Add equations:

2a = 18

a = 9

b = a - 14 = 9 - 14 = -5

The two numbers are 9 and -5.