The volume of a solid cylinder is 5852 cm³, and its height is 38 cm. What is the total surface area of the solid cylinder? (Round your answer to the nearest integer.) $$\text{(Use } \pi = \frac{22}{7} \text{)}$$​

Correct option is B

Given:
The volume of the solid cylinder is 5852 cm³.
The height of the cylinder is 38 cm.
Formula Used:
Volume of a cylinder = π r² h
Total surface area of a cylinder  = $$2\pi r (r + h)\\$$​
Solution:
V = π r² h
​$$5852 = \frac{22}{7} \times r^2 \times 38\\5852 = \frac{22 \times 38}{7} \times r^2\\5852 = \frac{836}{7} \times r^2\\40964 = 836 \times r^2\\r^2 = \frac{40964}{836} = 49\\r = \sqrt{49} = 7 \, \text{cm}\\$$​​
​$$A = 2\pi r (r + h)\\A = 2 \times \frac{22}{7} \times 7 \times (38 + 7)\\A = 2 \times \frac{22}{7} \times 7 \times 45\\A = 1980 \, \text{cm}^2\\$$​​