A cylindrical rod has an outer curved surface area of 5600 cm². If the length of the rod is 92 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is: (Take π = 22/7)

Correct option is B

Given:

Curved Surface Area (CSA) of cylinder = 5600 cm²

Height (h) = 92 cm

Find outer radius r (correct to 2 decimal places)

Formula Used:

CSA of a cylinder = 2πrh

Solution:

Using the formula;

5600 = $$2 \times \frac{22}{7} \times r \times 92$$​​

r = $$\frac{5600}{4048/7} = \frac{5600 \times 7}{4048}$$​​

r = $$\frac{39200}{4048} = 9.6881 \approx$$ 9.68 cm