arrow
arrow
arrow
The value of p2−(q−r)2(p+r)2−q2+q2−(p−r)2(p+q)2−r2+r2−(p−q)2(q+r)2−p2\frac{p^2 - (q - r)^2}{(p + r)^2 - q^2} + \frac{q^2 - (p - r)^2}{(p + q)^2 -
Question

The value of p2(qr)2(p+r)2q2+q2(pr)2(p+q)2r2+r2(pq)2(q+r)2p2\frac{p^2 - (q - r)^2}{(p + r)^2 - q^2} + \frac{q^2 - (p - r)^2}{(p + q)^2 - r^2} + \frac{r^2 - (p - q)^2}{(q + r)^2 - p^2} is​

A.

1

B.

2

C.

0

D.

3

Correct option is A

Given: 
p2(qr)2(p+r)2q2+q2(pr)2(p+q)2r2+r2(pq)2(q+r)2p2\frac{p^2 - (q - r)^2}{(p + r)^2 - q^2} + \frac{q^2 - (p - r)^2}{(p + q)^2 - r^2} + \frac{r^2 - (p - q)^2}{(q + r)^2 - p^2} 
Concept Used: 
We can find the value of the expression by letting the values of p, q and r.
Solution: 
Putting p = q = r = 1
p2(qr)2(p+r)2q2+q2(pr)2(p+q)2r2+r2(pq)2(q+r)2p2\frac{p^2 - (q - r)^2}{(p + r)^2 - q^2} + \frac{q^2 - (p - r)^2}{(p + q)^2 - r^2} + \frac{r^2 - (p - q)^2}{(q + r)^2 - p^2}

12(11)2(1+1)212+12(11)2(1+1)212+12(11)2(1+1)212\frac{1^2 - (1 - 1)^2}{(1 + 1)^2 - 1^2} + \frac{1^2 - (1 - 1)^2}{(1 + 1)^2 - 1^2} + \frac{1^2 - (1 - 1)^2}{(1 + 1)^2 - 1^2}
=13+13+13\frac{1}{3}+\frac{1}{3}+\frac{1}{3}
= 1
Thus, the value of the expression is 1. 

Free Tests

Free
Must Attempt

SSC CGL T-I Similar Paper (Held on 12 Sep 2025 S2)

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon200 Marks
  • timerIcon60 Mins
languageIcon English
Free
Must Attempt

SSC CGL T-I GA Section Test 01

languageIcon English
  • pdpQsnIcon25 Questions
  • pdpsheetsIcon50 Marks
  • timerIcon15 Mins
languageIcon English
Free
Must Attempt

SSC CGL T-I Full Mock Test 1 (Exam Level)

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon200 Marks
  • timerIcon60 Mins
languageIcon English
test-prime-package

Access ‘SSC CGL Tier I’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
383k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow