The value of ⁡$$\tanθ+\frac1{\tan⁡θ}$$​ is:

Correct option is D

Given:

$$tan\theta+\frac{1}{tan\theta}$$ 

Formula used:

​$$tan\theta= \frac{sin\theta}{cos\theta}$$ 

$$sin^2\theta+cos^2\theta=1$$ 

Solution:

​$$tan\theta+\frac{1}{tan\theta}$$​​

​$$\frac{sin\theta}{cos\theta}$$+ $$\frac{1}{\frac{sin\theta}{cos\theta}}$$ = $$\frac{sin\theta}{cos\theta}$$+$$\frac{cos\theta}{sin\theta}$$

$$\frac{sin^2\theta+cos^2\theta}{cos\theta\times sin\theta}$$= $$\frac{1}{cos\theta\times sin\theta}$$

= $$sec\theta cosec\theta$$

Thus the correct answer is (D)​​