The value of $$\sin(30^\circ) - \cos(60^\circ) + \tan(45^\circ) + \cosec(60^\circ)$$​ is:

Correct option is B

Given:

$$\sin(30^\circ) - \cos(60^\circ) + \tan(45^\circ) + \cosec(60^\circ)$$​

Formula Used: 

$$\sin(30^\circ) = \frac{1}{2}$$​

$$​\cos(60^\circ) = \frac{1}{2}$$​

$$\tan(45^\circ) = 1$$​​

$$\cosec(60^\circ) = \frac{2}{\sqrt{3}}$$ 

Solution:  

​$$\sin(30^\circ) - \cos(60^\circ) + \tan(45^\circ) + \cosec(60^\circ)$$​

= $$\frac12-\frac12+1+\frac2{\sqrt3}$$ 

= $$1+ \frac2{\sqrt3}$$ 

= $$\frac{\sqrt3+2}{\sqrt3}$$​ $$\times \frac{\sqrt{3}}{\sqrt{3}}$$ 

= $$\frac{3+2\sqrt3}3$$​