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The value of (cosec A + cot A) (1 – cos A) is:
Question

The value of (cosec A + cot A) (1 – cos A) is:

A.

sin A

B.

tan A

C.

cos A

D.

cot A

Correct option is A

Given: 

(cosecA+cotA)(1cosA)(\cosec A + \cot A) (1 – \cos A) 

Formula Used:

Trigonometric identities:

cosecA=1sinA cotA=cosAsinA sin2A+cos2A=1 a2b2=(ab)(a+c)\cosec A = \frac{1}{\sin A}\\ \ \\\cot A = \frac{\cos A}{\sin A}\\ \ \\\sin^2A + \cos^2A = 1\\ \ \\a^2 – b^2 = (a-b)(a+c)​​

Solution:

(cosecA+cotA)(1cosA) =(1sinA+cosAsinA)(1cosA) =(1+cosAsinA)(1cosA) =(1+cosA)(1cosA)sinA =sin2AsinA=sinA(\cosec A + \cot A)(1 - \cos A)\\ \ \\ = \left(\frac{1}{\sin A} + \frac{\cos A}{\sin A}\right)(1-\cos A)\\ \ \\= \left(\frac{1 + \cos A}{\sin A}\right)(1 - \cos A) \\ \ \\ = \frac{(1 + \cos A)(1 - \cos A)}{\sin A} \\ \ \\= \frac{\sin^2 A}{\sin A} = \sin A​​​

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