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    The value of cos² 29° + cos² 61° is:
    Question

    The value of cos² 29° + cos² 61° is:

    A.

    32\frac{\sqrt{3}}{2}​​

    B.

    2

    C.

    1

    D.

    0

    Correct option is C

    Sol.

    Given:

    cos² 29° + cos² 61°

    Formula Used:

    sin2(θ)+cos2(θ)=1cos(90θ)=sin(θ)\sin^2(\theta) + \cos^2(\theta) = 1 \\\cos(90^\circ - \theta) = \sin(\theta)\\

    Solution:

    cos2(29)+cos2(61)cos2(29)+sin2(9061)cos2(29)+sin2(29)=1(sin2(θ)+cos2(θ)=1)\cos^2(29^\circ) + \cos^2(61^\circ)\\\cos^2(29^\circ) + \sin^2(90^\circ - 61^\circ)\\\cos^2(29^\circ) + \sin^2(29^\circ)\\= 1 ( \sin^2(\theta) + \cos^2(\theta) = 1)\\

    ​​

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