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    The value of cos⁡23∘+cos⁡24∘+cos⁡25∘+⋯+cos⁡287∘\cos^{2}3^{\circ} + \cos^{2}4^{\circ} + \cos^{2}5^{\circ} + \dots + \cos^{2}87^{\circ}cos23∘+cos24
    Question

    The value of cos23+cos24+cos25++cos287\cos^{2}3^{\circ} + \cos^{2}4^{\circ} + \cos^{2}5^{\circ} + \dots + \cos^{2}87^{\circ} is:​

    A.

    552\frac{55}{2}​​

    B.

    652\frac{65}{2}​​

    C.

    752\frac{75}{2}​​

    D.

    852\frac{85}{2}​​

    Correct option is D

    Given:

    cos23+cos24+cos25++cos287\cos^2 3^\circ + \cos^2 4^\circ + \cos^2 5^\circ + \cdots + \cos^2 87^\circ​​

    Formula Used:

    cos2θ+cos2(90θ)=1\cos^2 \theta + \cos^2 (90^\circ - \theta) = 1​​

    cos245=12\cos^2 45^\circ = \frac{1}{2}​​

    Solution:

    The angles range from 33^\circ to 8787^\circ​, forming 85 - 3 + 1 = 85 terms.

    Pair the terms symmetrically:

    Each pair sums to 1.

    Total pairs: 842\frac{84}{2}​ = 42 pairs (as the terms are symmetric).

    the unpaired middle term: cos245=12\cos^2 45^\circ = \frac{1}{2}​​

    Total sum = 42×1+12=84+12=85242 \times 1 + \frac{1}{2} = \frac{84 + 1 }{2} = \frac{85}{2}​​

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