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The value of cos⁡23∘+cos⁡24∘+cos⁡25∘+⋯+cos⁡287∘\cos^{2}3^{\circ} + \cos^{2}4^{\circ} + \cos^{2}5^{\circ} + \dots + \cos^{2}87^{\circ}cos23∘+cos24
Question

The value of cos23+cos24+cos25++cos287\cos^{2}3^{\circ} + \cos^{2}4^{\circ} + \cos^{2}5^{\circ} + \dots + \cos^{2}87^{\circ} is:​

A.

552\frac{55}{2}​​

B.

652\frac{65}{2}​​

C.

752\frac{75}{2}​​

D.

852\frac{85}{2}​​

Correct option is D

Given:

cos23+cos24+cos25++cos287\cos^2 3^\circ + \cos^2 4^\circ + \cos^2 5^\circ + \cdots + \cos^2 87^\circ​​

Formula Used:

cos2θ+cos2(90θ)=1\cos^2 \theta + \cos^2 (90^\circ - \theta) = 1​​

cos245=12\cos^2 45^\circ = \frac{1}{2}​​

Solution:

The angles range from 33^\circ to 8787^\circ​, forming 85 - 3 + 1 = 85 terms.

Pair the terms symmetrically:

Each pair sums to 1.

Total pairs: 842\frac{84}{2}​ = 42 pairs (as the terms are symmetric).

the unpaired middle term: cos245=12\cos^2 45^\circ = \frac{1}{2}​​

Total sum = 42×1+12=84+12=85242 \times 1 + \frac{1}{2} = \frac{84 + 1 }{2} = \frac{85}{2}​​

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