The value of 2sin30° + 5cos60° + 3sin180° is:

Correct option is B

Given:

$$2\sin(30^\circ) + 5\cos(60^\circ) + 3\sin(180^\circ)$$ 

Concept Used:

$$\sin(30^\circ) = \frac{1}{2},$$ 

​$$\cos(60^\circ) = \frac{1}{2},$$ 

$$\sin(180^\circ) = 0$$ 

Solution:

Given expression:

​$$2\sin(30^\circ) + 5\cos(60^\circ) + 3\sin(180^\circ)$$ 

Now, substitute these values into the expression:

= $$2 \left( \frac{1}{2} \right) + 5 \left( \frac{1}{2} \right) + 3(0)$$ 

= $$1+ \frac{5}{2}$$ 

= $$\frac{7}{2}$$ 

​So, the solution is: $$\frac{7}{2}$$ .​