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​cos231°+cos259°cos^231°+cos^259°cos231°+cos259°​ is equal to:
Question

cos231°+cos259°cos^231°+cos^259°​ is equal to:

A.

2sin231°2\sin^2 31°

B.

0

C.

1

D.

2cos231°2\cos^2 31°

Correct option is C

Given:

cos231°+cos259°\cos^2 31° + \cos^2 59°​​

Formula Used:

sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1​​

cosθ=sin(90°θ)\cos \theta = \sin(90° - \theta)​​

Solution:

cos231°+cos259°\cos^2 31° + \cos^2 59°​​

=sin2(90°31°)+cos259°=\sin^2(90° - 31°) + \cos^2 59°​​

=sin2(59°)+cos259°=\sin^2(59°) + \cos^2 59°​​

=1

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