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    ​cos231°+cos259°cos^231°+cos^259°cos231°+cos259°​ is equal to:
    Question

    cos231°+cos259°cos^231°+cos^259°​ is equal to:

    A.

    2sin231°2\sin^2 31°

    B.

    0

    C.

    1

    D.

    2cos231°2\cos^2 31°

    Correct option is C

    Given:

    cos231°+cos259°\cos^2 31° + \cos^2 59°​​

    Formula Used:

    sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1​​

    cosθ=sin(90°θ)\cos \theta = \sin(90° - \theta)​​

    Solution:

    cos231°+cos259°\cos^2 31° + \cos^2 59°​​

    =sin2(90°31°)+cos259°=\sin^2(90° - 31°) + \cos^2 59°​​

    =sin2(59°)+cos259°=\sin^2(59°) + \cos^2 59°​​

    =1

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