If sin(3A – 20°) = cos(20° – 3B), then the value of A – B is:
Given:
sin(3A - 20°) = cos(20° - 3B)
Concept Used:
sin(x) = cos(90° - x)
Solution:
cos(90° - (3A - 20°)) = cos(20° - 3B)
cos(90° - 3A + 20°) = cos(20° - 3B)
cos(110° - 3A) = cos(20° - 3B)
110° - 3A = 20° - 3B
110° - 20° = 3A - 3B
90° = 3(A - B)
A - B = 30°
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