The sum of three consecutive odd numbers is 20 more than the first of these numbers. Find the largest of these numbers.

Correct option is A

Given:
The sum of three consecutive odd numbers is 20 more than the first of these numbers.
Solution:
Let the number be (n -2), n and (n+2)
According to the question
(n -2) + n + (n+2) = (n – 2) + 20
3n = (n – 2) + 20
2n = 18
n = 9
Therefore, the largest number be (n+2) = 9+2 = 11