The sum of five numbers is 655. The average of the first two numbers is 78 and the third number is 101. Find the average of the remaining two numbers?

Correct option is A

Given:

The sum of five numbers is 655.

The average of the first two numbers is 78.

The third number is 101.

We need to find the average of the remaining two numbers.

Formula Used:

Average =$$\frac{\text{Sum of numbers}}{\text{Number of numbers}}$$​

Solution:

Let the five numbers be a, b, c, d, and e.

From the given information:

a + b + c + d + e = 655 (sum of the five numbers)

The average of the first two numbers is 78, so:

​$$\frac{a + b}{2} = 78$$​

a + b = 7$$8 \times 2 = 15$$​6

The third number is 101, so:

c = 101

Now, 156 + 101 + d + e = 655

257 + d + e = 655

d + e = 655 - 257 = 398

Average of d and e $$= \frac{d + e}{2} = \frac{398}{2}$$​ = 199

So, the average of the remaining two numbers is 199.