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    ​The sum of all natural numbers from 75 to 97 is:​
    Question

    Directions: Choose the correct alternative.


    The sum of all natural numbers from 75 to 97 is:

    A.

    1598

    B.

    1798

    C.

    1958

    D.

    1978

    Correct option is D

    Given:

    We need to find the sum of all natural numbers from 75 to 97.

    Formula used:

    The sum of an arithmetic series (sequence of numbers with a constant difference between them) can be calculated using the formula:

    Sn=n2×(a+l) S_n = \frac{n}{2} \times (a + l)

    l=a+(n1)×dl = a + (n - 1) \times d

    where:

    n is the number of terms,
    a is the first term,
    l is the last term.

    Solution:

    First term, a = 75,
    Last term, l = 97,

    The common difference between the terms is 1 (since the numbers are consecutive).

    Put the values in formula ,

    l=a+(n1)×dl = a + (n - 1) \times d​​

    97=75+(n1)×197 = 75 + (n - 1) \times 1

    97 − 75 = n − 1

    n = 23

    Sn=n2×(a+l) S_n = \frac{n}{2} \times (a + l)

    Sn=232×(75+97)S_n = \frac{23}{2} \times (75 + 97)

    Sn=232×172S_n= \frac{23}{2} \times 172

    Sn=23×86S_n = 23 \times 86

    Sn=1978​​​S_n = 1978​​​

    Thus, the correct answer is (d).

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