The smallest natural number which is divisible by 33, 6, 8 and 16 is:

Correct option is D

Given:

Smallest natural number divisible by 33, 6, 8, and 16:

Concept Used:

Least Common Multiple (LCM)

The smallest natural number divisible by a set of numbers is their Least Common Multiple (LCM).

Solution:

Prime Factorization: Find the prime factorization of each number:

33 = 3 $$\times$$​ 11

6 = 2$$\times$$3​

8 =$$2^3$$​​

16 = $$2^4$$​​

​Multiply the highest powers of the prime factors together:

LCM = $$2^4 × 3^1×11^1$$​= 16 $$\times$$3$$\times$$11 = 528​​​​

Therefore, the smallest natural number divisible by 33, 6, 8, and 16 is 528.

Option (d) is right.