The smallest natural number which is divisible by 24, 58, 48 and 12 is:

Correct option is B

Given:
Numbers to find the smallest natural number divisible by 24, 58, 48, and 12.
Formula Used:
The smallest natural number divisible by multiple numbers is the Least Common Multiple (LCM) of those numbers.
Solution:
​$$24 = 2^3 × 3\\58 = 2 × 29\\48 = 2^4 × 3\\12 = 2^2 × 3\\$$​​
LCM = $$2^4 × 3 × 29 = 16 × 3 × 29 = 1392$$​​
The smallest natural number divisible by 24, 58, 48, and 12 is 1392.