The smallest natural number which is divisible by 16, 88, 12 and 22 is:

Correct option is D

Given:

To find the smallest natural number divisible by 16, 88, 12, and 22.

Concept Used:

The smallest natural number divisible by a set of numbers is the Least Common Multiple (LCM) of those numbers.

Solution:

Prime factorization of the numbers:

16 = $$2^4$$​​

88 = $$2^3 \times 11$$​​

12 = $$2^2 \times 3$$​​

22 = $$2 \times 11$$​​

LCM = $$2^4 \times 3^1 \times 11^1 = 16 \times 3 \times 11$$​ = 528