The smallest natural number which is divisible by 12, 8, 75 and 15 is:

Correct option is B

​Given:

The smallest natural number which is divisible by 12, 8, 75 and 15 is.

Concept Used:

The LCM of two or more integers is the smallest positive integer that is a multiple of all the given integers.

Solution:

12 = $$2^2 \times 3^1$$​​
8 = $$2^3$$​​
75 =$$3^1 \times 5^2$$​​
15 =$$3^1 \times 5^1$$​​
Highest powers:
($$2^3$$​) (from 8)
($$3^1$$​) (from 12, 75, 15)
($$5^2$$​) (from 75)
​$$\text{LCM} = 2^3 \times 3^1 \times 5^2$$​​
​$$\text{LCM} = 8 \times 3 \times 25 = 600$$​
Option (B) is right.