The semicircle of area 1250 π cm² is inscribed inside a rectangle. The diameter of the semicircle coincides with the length of the rectangle. The area of the rectangle is:

Correct option is A

Given:
Length of the Rectangle = Diameter of the semicircle
The semicircle of area =1250 π $$cm^2$$​​
Formula Used:
Area of semicircle =$$\frac{π × r^2}2$$​​
Area of rectangle = Length × Width
Solution:

According to the given conditions,
Let the length of the rectangle = 2r
Width of the rectangle = r
Area of rectangle = 2r × r
Area of rectangle = 2r2
Area of semicircle =$$\frac{π × r^2}2$$​
1250 π = $$\frac{π × r^2}2$$​​
=> $$r^2$$​ = 2500
=> r = 50
Area of rectangle = 2r × r = 2$$r^2$$​​
Area of rectangle= 5000 $$cm^2$$​​