In a circle of radius 10.5 cm, if the angle of a sector is $$\frac{2\pi}{3}$$, then the perimeter of the sector is (in cm): $$(Take \pi = \frac{22}{7})$$​​

Correct option is B

Given:

Radius of the circle r = 10.5 cm

Angle of sector θ = $$\frac{2\pi}{3}$$​ radians

Formula Used:

Perimeter of a sector = arc length + 2 × radius

Arc length (in radians) = r × θ

Solution:

Arc Length = $$10.5 \times \frac{2\pi}{3}$$​​

​$$= 10.5 \times \frac{2 \times \frac{22}{7}}{3}$$​​

​$$= 10.5 \times \frac{44}{21}$$​​

​$$= \frac{462}{21} = 22 \text{ cm}$$​​

Perimeter of sector = 22 + 2 × 10.5 = 22 + 21 = 43 cm