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The ratio of the present ages of two persons A and B is 4:3. If 4 years ago, the ratio of their ages was 2:1. what is the present age of A and B (in y
Question



The ratio of the present ages of two persons A and B is 4:3. If 4 years ago, the ratio of their ages was 2:1. what is the present age of A and B (in years) respectively?

A.

8, 6

B.

9, 7

C.

12, 9

D.

9, 12

Correct option is A

Solution:

Let the present ages of A and B be:
A = 4x
B = 3x
Four years ago:
A’s age = 4x − 4
B’s age = 3x − 4

According to the question:
(4x − 4) / (3x − 4) = 2 / 1

Cross-multiplying:
4x − 4 = 2 × (3x − 4)
4x − 4 = 6x − 8

Now solve:
6x − 4x = 8 − 4
2x = 4
x = 2

Now plug the value of x:
A = 4 × 2 = 8 years
B = 3 × 2 = 6 years

Final Answer:
(a) 8, 6

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