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    The ratio of the present ages of two persons A and B is 4:3. If 4 years ago, the ratio of their ages was 2:1. what is the present age of A and B (in y
    Question



    The ratio of the present ages of two persons A and B is 4:3. If 4 years ago, the ratio of their ages was 2:1. what is the present age of A and B (in years) respectively?

    A.

    8, 6

    B.

    9, 7

    C.

    12, 9

    D.

    9, 12

    Correct option is A

    Solution:

    Let the present ages of A and B be:
    A = 4x
    B = 3x
    Four years ago:
    A’s age = 4x − 4
    B’s age = 3x − 4

    According to the question:
    (4x − 4) / (3x − 4) = 2 / 1

    Cross-multiplying:
    4x − 4 = 2 × (3x − 4)
    4x − 4 = 6x − 8

    Now solve:
    6x − 4x = 8 − 4
    2x = 4
    x = 2

    Now plug the value of x:
    A = 4 × 2 = 8 years
    B = 3 × 2 = 6 years

    Final Answer:
    (a) 8, 6

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