The ratio of the present ages of A to B is 16:9, respectively. If the age of A eight years hence is twice the age of B two years hence, then find the present age of B (in years).

Correct option is C

Let the present ages of A and B be 16a and 9a respectively
ATQ,
$$\frac{16a + 8}{9a + 2} = \frac{2}{1}$$​
16a + 8 = 18a + 4
4 = 2a
a = 2
The present age of B = 9a = 18 years