The radius of the base of a solid cone is 21 cm and its height is 9 cm. What is the volume of the cone?

Correct option is C

Given:

Radius, r = 21 cm

Height, h = 9 cm

Formula Used:

Volume of the cone = $$\frac{1}{3} \pi r^2 h$$​​

Solution:

Volume of the cone = $$\frac{1}{3} \times \pi \times 21^2 \times 9$$​​

​$$= \frac{1}{3} \times \frac{22}7 \times 441 \times 9$$​​

​$$= 4158 \ cm^3$$​​