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The principal value of cot−1(−13)\text{cot}^{-1}(\frac{-1}{\sqrt3})cot−1(3​−1​)​ is:
Question

The principal value of cot1(13)\text{cot}^{-1}(\frac{-1}{\sqrt3})​ is:

A.

π6\frac{π}{6}​​

B.

2π3\frac{2π}{3}​​

C.

3π2\frac{3π}{2}​​

D.

π3\frac{π}{3}​​

Correct option is B

Given:

We are to find the principal value of:

cot1(13)\cot^{-1}\left(-\frac{1}{\sqrt{3}}\right)​​

Concept Used:

cot1(13)=π3,\cot^{-1}\left(\frac{1}{\sqrt{3}}\right) = \frac{\pi}{3},​​

since

cot(π3)=13\cot\left(\frac{\pi}{3}\right) = \frac{1}{\sqrt{3}}​​

For negative arguments, we use:

cot1(x)=πcot1(x)\cot^{-1}(-x) = \pi - \cot^{-1}(x)​​

Solution:

cot1(13)=ππ3=2π3\cot^{-1}\left(-\frac{1}{\sqrt{3}}\right) = \pi - \frac{\pi}{3} = \frac{2\pi}{3}​​

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