The perimeter of two squares are 48 cm and 60 cm. Find the perimeter of a third square whose area is equal to the difference of the area of the square.

Correct option is C

Given:

The perimeters of two squares are 48 cm and 60 cm.

Formula used:

Perimeter of a square = 4 × side

Area of a square = side²

Solution:

First square:

Perimeter = 48 cm

=> 4 × side₁= 48

=> side₁= 48 / 4 = 12 cm

Area₁= 12²= 144 cm²

Second square:

Perimeter = 60 cm

=> 4 × side₂= 60

=> side₂= 60 / 4 = 15 cm

Area₂= 15²= 225 cm²

Third square:

Area₃= Area₂- Area₁= 225 - 144 = 81 cm²

Side₃= √81 = 9 cm

Perimeter₃= 4 × side₃= 4 × 9 = 36 cm

∴ The correct answer is (c).