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The least value of 2sin2θ+3cos2θ2\text{sin}^2θ+3\text{cos}^2θ2sin2θ+3cos2θ​ is:
Question

The least value of 2sin2θ+3cos2θ2\text{sin}^2θ+3\text{cos}^2θ​ is:

A.

1

B.

5

C.

3

D.

2

Correct option is D

Given:

2sin2θ+3cos2θ2\text{sin}^2θ+3\text{cos}^2θ

Formula Used:

sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1

Solution:

2sin2θ+3cos2θ2\text{sin}^2θ+3\text{cos}^2θ

2(1cos2θ)+3cos2θ2(1 - \cos^2\theta) + 3\cos^2\theta

22cos2θ+3cos2θ2 - 2\cos^2\theta + 3\cos^2\theta

=2+cos2θ= 2 + \cos^2\theta

​​Since the minimum value of cos2θ\cos^2\theta​ is 0,

= 2 + 0

= 2

Thus, the correct answer is (d).

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