The least number, which when divided by 18, 30, 40 and 45 leaves in each case a remainder of 7, is:

Correct option is A

Given:

We need to find the least number N which, when divided by 18, 30, 40, and 45, leaves a remainder of 7 in each case. 

Solution:

LCM of 18, 30, 40, and 45.

18 = $$2 \times 3^2$$​​

30 = $$2 \times 3 \times 5$$​​

40 = $$2^3 \times 5$$​​

45 $$= 3^2 \times 5$$​​

LCM = $$2^3 \times 3^2 \times 5 = 8 \times 9 \times 5 = 360$$​

The least number N that leaves a remainder of 7 when divided by 18, 30, 40, and 45 is:

N = 360 + 7 = 367