The HCF of

$$\frac{9}{10},\frac{3}{25},\frac{6}{15}$$​ and $$\frac{12}{5}$$​ is:

Correct option is B

Given:
Fractions: $$\frac{9}{10},\frac{3}{25},\frac{6}{15}$$​ and $$\frac{12}{5}$$​​
Formula Used:
​$$\text{HCF of Fractions} = \frac{\text{HCF of Numerators}}{\text{LCM of Denominators}}$$​​
Solution:
H.C.F of 9, 3, 6, and 12 is 3.
L.C.M of 10, 25, 15, and 5 is 150.
Thus, HCF of the fractions = $$\frac{3} { 150} = \frac1{50}.$$​​
Therefore, the HCF of the given fractions is $$\frac1{50}.$$​​