The HCF of $$\frac{1}{3}$$​,$$\frac{2}{3}$$​,$$\frac{2}{9}$$​  and $$\ \frac{3}{12}$$​ is:

Correct option is A

Given:

Number given are$$\frac{1}{3},\frac{2}{3},\frac{2}{9}\ and \ \frac{3}{12}$$​​

Formula Used:

HCF of fractions =$$\frac{HCF\ of\ Numerators}{LCM\ of\ denominators}$$​​

Solution:

$$HCF\ of \ \left(\frac{1}{3},\frac{2}{3},\frac{2}{9}, \frac{3}{12}\right) = \frac{HCF\ of\ 1,2,2,3}{LCM\ of\ 3,3,9,12}=\frac{1}{36}$$​​

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