The greatest number which on dividing 50, 58 and 69 leaves remainders of 1, 2 and 6, respectively, is:
Given:
Given numbers are 50,58 and 69
Remainder left in each case 1, 2 and 6
Formula Used:
The highest number which divides the numbers is HCF
Solution:
The number to be taken will be (50-1), (58-2) and (69-6)
So, the HCF of 49,56 and 63 will be
49 =
56=
63 =
HCF = 7
English
100 Questions
100 Marks
90 Mins English English100 Questions100 Marks90 Mins English English100 Questions100 Marks90 Mins EnglishLet p be the greatest number of 4-digits which when divided by 21, 22, 24 and 28, the remainder in each case is 8. What is the sum of the digits of p?
The least number of five digits which is exactly divisible by 75 is :
Which of the following numbers is divisible by 99?
The greatest number that divides 63, 75 and 93 leaving remainder 3 in each case is:
The least number of five digits which is exactly divisible by 75 is:
The difference between the largest and the smallest 5-digit numbers made of digits 2, 3, 5, 0 and 9
From a four digit number, a number formed by reversing the digits is subtracted. The new number is always divisible by
Write the largest 5 digit number which when divided by 469 leaves 3 as remainder
The sum of the largest and the smallest 5-digit numbers formed by the digits 3, 4, 0, 6, 5 is
Write the smallest 5-digit number using digits 2, 3, 5, 8 and 9 which is divisible by 9
Suggested Test Series
Suggested Test Series
