The greatest number which on dividing 50, 58 and 69 leaves remainders of 1, 2 and 6, respectively, is:
Given:
Given numbers are 50,58 and 69
Remainder left in each case 1, 2 and 6
Formula Used:
The highest number which divides the numbers is HCF
Solution:
The number to be taken will be (50-1), (58-2) and (69-6)
So, the HCF of 49,56 and 63 will be
49 =
56=
63 =
HCF = 7
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