The equation of the plane that passes through (1, -1 2) and has direction ratios (1, 2, 3) is:

Correct option is B

​$$\begin{aligned}&\textbf{Given:} \\&\text{Point on the plane: } (x_0, y_0, z_0) = (1, -1, 2) \\&\text{Normal vector to the plane: } \vec{n} = (1, 2, 3) \\\\&\text{ \quad \textbf{General equation of a plane:}} \\&a(x - x_0) + b(y - y_0) + c(z - z_0) = 0 \\\\&\text{Substitute:} \\&1(x - 1) + 2(y + 1) + 3(z - 2) = 0 \\\\&\text{Simplify:} \\&(x - 1) + 2y + 2 + 3z - 6 = 0 \\&x + 2y + 3z - 5 = 0\end{aligned}$$​​