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Find the distance between two points (2, 6, 5) and (2, 3, 9).
Question

Find the distance between two points (2, 6, 5) and (2, 3, 9).

A.

5 units

B.

0 units

C.

7 units

D.

4 units

Correct option is A

Distance formula:Distance=(x2x1)2+(y2y1)2+(z2z1)2Step-by-Step Calculation:1. Identify the coordinates:Point A(x1,y1,z1)=(2,6,5)Point B(x2,y2,z2)=(2,3,9)2. Compute the differences:x2x1=22=0y2y1=36=3z2z1=95=43. Square the differences:02=0(3)2=942=164. Sum the squared differences:0+9+16=255. Take the square root:25=5\begin{aligned}&\text{Distance formula:} \\&\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2} \\\\&\text{Step-by-Step Calculation:} \\&\textbf{1. Identify the coordinates:} \\&\quad \text{Point } A(x_1, y_1, z_1) = (2, 6, 5) \\&\quad \text{Point } B(x_2, y_2, z_2) = (2, 3, 9) \\\\&\textbf{2. Compute the differences:} \\&\quad x_2 - x_1 = 2 - 2 = 0 \\&\quad y_2 - y_1 = 3 - 6 = -3 \\&\quad z_2 - z_1 = 9 - 5 = 4 \\\\&\textbf{3. Square the differences:} \\&\quad 0^2 = 0 \\&\quad (-3)^2 = 9 \\&\quad 4^2 = 16 \\\\&\textbf{4. Sum the squared differences:} \\&\quad 0 + 9 + 16 = 25 \\\\&\textbf{5. Take the square root:} \\&\quad \sqrt{25} = 5\end{aligned}​​

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