Find mid point of (4, 3, 6) and (6, 5, 12).

Correct option is B

​$$\begin{aligned}&\text{Formula:} \\&\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}, \frac{z_1 + z_2}{2} \right) \\[10pt]&\textbf{Step-by-Step Calculation:} \\[5pt]&1. \ \text{Identify the coordinates of points } A \text{ and } B: \\&\quad A(x_1, y_1, z_1) = (4, 3, 6) \\&\quad B(x_2, y_2, z_2) = (6, 5, 12) \\[5pt]&2. \ \text{Apply the midpoint formula:} \\&\quad \text{Midpoint} = \left( \frac{4 + 6}{2}, \frac{3 + 5}{2}, \frac{6 + 12}{2} \right) \\[5pt]&3. \ \text{Simplify each component:} \\&\quad \text{Midpoint} = \left( \frac{10}{2}, \frac{8}{2}, \frac{18}{2} \right) = (5, 4, 9)\end{aligned}$$​​