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The distance from the origin to the line 4x+3y+6=0 is:
Question

The distance from the origin to the line 4x+3y+6=0 is:

A.

7/5

B.

4/5

C.

6/5

D.

3/5

Correct option is C

Given: The equation of the line is 4x + 3y + 6 = 0.
Formula Used: The distance from a point (x₁, y₁) to the line Ax + By + C = 0 is given by:
Distance = Ax1+By1+CA2+B2\frac {|Ax₁ + By₁ + C| } {\sqrt {A² + B²}}​​

Solution:
On comparing with the standard equation,
A = 4, B = 3, C = 6, and the point (x₁, y₁) = (0, 0).
Distance=(4)(0)+(3)(0)+642+32=616+9=625=65units.\text{Distance} = \frac{|(4)(0) + (3)(0) + 6|}{\sqrt{4^2 + 3^2}} \\= \frac{|6|}{\sqrt{16 + 9}} \\= \frac{6}{\sqrt{25}} \\= \frac{6}{5} { units.}​​

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