The area of the figure formed by joining the mid-points of the adjacent sides of a rhombus with diagonals 12 cm and 16, cm is:

Given:
​$$d_1 = 12 \, \text{cm}, \quad d_2 = 16 \, \text{cm} \\$$​​
Concept used:
Area of rhombus $$= \frac{1}{2} d_1 d_2 \\$$​​
When midpoints of adjacent sides of a rhombus are joined, the resulting figure is a rectangle whose area is half the area of the rhombus.
Solution:
Area of rhombus $$= \frac{1}{2} \cdot 12 \cdot 16 = 96 \, \text{cm}^2 \\$$​​
Area of rectangle formed $$= \frac{1}{2} \cdot 96 = 48 \, \text{cm}^2 \\$$​​
Correct answer is (a)