The ratio in which the line segment joining the points (5, -2) and  (0, 7) is divided by the point $$\left( \frac{5}{3}, 4 \right)$$​ is:

A = (5, -2)

B = (0, 7)

Point dividing AB: P = (5/3, 4)

​Concept used :
Using the section formula:
If a point P(x, y)  divides the line joining  $$A(x_1, y_1)$$​ and  $$B(x_2, y_2)$$​ in the ratio } m:n, then:}
​$$x = \frac{mx_2 + nx_1}{m + n}, \quad y = \frac{my_2 + ny_1}{m + n} \\$$​​
Solution:
​$$x = \frac{m \cdot 0 + n \cdot 5}{m + n} = \frac{5n}{m + n} = \frac{5}{3} \\\Rightarrow \frac{5n}{m + n} = \frac{5}{3} \Rightarrow \frac{n}{m + n} = \frac{1}{3} \\\Rightarrow 3n = m + n \Rightarrow 2n = m \Rightarrow \frac{m}{n} = \frac{2}{1} \\$$​​
Correct answer is (c) 2 : 1
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